Solve for c c+(4-3c)-2=0

$c + (4 - 3 c) - 2 = 0$

Step 1

Simplify $c + 4 - 3 c - 2$ .

Subtract $3 c$ from $c$ .

$- 2 c + 4 - 2 = 0$

Subtract $2$ from $4$ .

$- 2 c + 2 = 0$

Step 2

Subtract $2$ from both sides of the equation.

$- 2 c = - 2$

Step 3

Divide each term in $- 2 c = - 2$ by $- 2$ and simplify.

Divide each term in $- 2 c = - 2$ by $- 2$ .

$\frac{- 2 c}{- 2} = \frac{- 2}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 c}{- 2} = \frac{- 2}{- 2}$

Divide $c$ by $1$ .

$c = \frac{- 2}{- 2}$

Simplify the right side.

Divide $- 2$ by $- 2$ .

$c = 1$