Solve for c f=(9c)/5+32

$f = \frac{9 c}{5} + 32$

Step 1

Rewrite the equation as $\frac{9 c}{5} + 32 = f$ .

$\frac{9 c}{5} + 32 = f$

Step 2

Subtract $32$ from both sides of the equation.

$\frac{9 c}{5} = f - 32$

Step 3

Multiply both sides of the equation by $\frac{5}{9}$ .

$\frac{5}{9} \cdot \frac{9 c}{5} = \frac{5}{9} (f - 32)$

Step 4

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{5}{9} \cdot \frac{9 c}{5}$ .

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5}{9} \cdot \frac{9 c}{5} = \frac{5}{9} (f - 32)$

Rewrite the expression.

$\frac{1}{9} (9 c) = \frac{5}{9} (f - 32)$

Cancel the common factor of $9$ .

Factor $9$ out of $9 c$ .

$\frac{1}{9} (9 (c)) = \frac{5}{9} (f - 32)$

Cancel the common factor.

$\frac{1}{9} (9 c) = \frac{5}{9} (f - 32)$

Rewrite the expression.

$c = \frac{5}{9} (f - 32)$

Simplify the right side.

Simplify $\frac{5}{9} (f - 32)$ .

Apply the distributive property.

$c = \frac{5}{9} f + \frac{5}{9} \cdot - 32$

Combine $\frac{5}{9}$ and $f$ .

$c = \frac{5 f}{9} + \frac{5}{9} \cdot - 32$

Multiply $\frac{5}{9} \cdot - 32$ .

Combine $\frac{5}{9}$ and $- 32$ .

$c = \frac{5 f}{9} + \frac{5 \cdot - 32}{9}$

Multiply $5$ by $- 32$ .

$c = \frac{5 f}{9} + \frac{- 160}{9}$

Move the negative in front of the fraction.

$c = \frac{5 f}{9} - \frac{160}{9}$