Solve for c p=r-c

$p = r - c$

Step 1

Rewrite the equation as $r - c = p$ .

$r - c = p$

Step 2

Subtract $r$ from both sides of the equation.

$- c = p - r$

Step 3

Divide each term in $- c = p - r$ by $- 1$ and simplify.

Divide each term in $- c = p - r$ by $- 1$ .

$\frac{- c}{- 1} = \frac{p}{- 1} + \frac{- r}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{c}{1} = \frac{p}{- 1} + \frac{- r}{- 1}$

Divide $c$ by $1$ .

$c = \frac{p}{- 1} + \frac{- r}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{p}{- 1}$ .

$c = - 1 \cdot p + \frac{- r}{- 1}$

Rewrite $- 1 \cdot p$ as $- p$ .

$c = - p + \frac{- r}{- 1}$

Dividing two negative values results in a positive value.

$c = - p + \frac{r}{1}$

Divide $r$ by $1$ .

$c = - p + r$