Solve for C P=(R-C)/N

$P = \frac{R - C}{N}$

Step 1

Rewrite the equation as $\frac{R - C}{N} = P$ .

$\frac{R - C}{N} = P$

Step 2

Multiply both sides by $N$ .

$\frac{R - C}{N} N = P N$

Step 3

Simplify the left side.

Simplify $\frac{R - C}{N} N$ .

Cancel the common factor of $N$ .

Cancel the common factor.

$\frac{R - C}{N} N = P N$

Rewrite the expression.

$R - C = P N$

Reorder $R$ and $- C$ .

$- C + R = P N$

Step 4

Solve for $C$ .

Subtract $R$ from both sides of the equation.

$- C = P N - R$

Divide each term in $- C = P N - R$ by $- 1$ and simplify.

Divide each term in $- C = P N - R$ by $- 1$ .

$\frac{- C}{- 1} = \frac{P N}{- 1} + \frac{- R}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{C}{1} = \frac{P N}{- 1} + \frac{- R}{- 1}$

Divide $C$ by $1$ .

$C = \frac{P N}{- 1} + \frac{- R}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{P N}{- 1}$ .

$C = - 1 \cdot (P N) + \frac{- R}{- 1}$

Rewrite $- 1 \cdot (P N)$ as $- (P N)$ .

$C = - (P N) + \frac{- R}{- 1}$

Dividing two negative values results in a positive value.

$C = - P N + \frac{R}{1}$

Divide $R$ by $1$ .

$C = - P N + R$