Solve for d 1/6d+2/3=1/4(d-2)

$\frac{1}{6} d + \frac{2}{3} = \frac{1}{4} (d - 2)$

Step 1

Combine $\frac{1}{6}$ and $d$ .

$\frac{d}{6} + \frac{2}{3} = \frac{1}{4} \cdot (d - 2)$

Step 2

Simplify $\frac{1}{4} \cdot (d - 2)$ .

Apply the distributive property.

$\frac{d}{6} + \frac{2}{3} = \frac{1}{4} d + \frac{1}{4} \cdot - 2$

Combine $\frac{1}{4}$ and $d$ .

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{1}{4} \cdot - 2$

Cancel the common factor of $2$ .

Factor $2$ out of $4$ .

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{1}{2 (2)} \cdot - 2$

Factor $2$ out of $- 2$ .

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{1}{2 \cdot 2} \cdot (2 \cdot - 1)$

Cancel the common factor.

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{1}{2 \cdot 2} \cdot (2 \cdot - 1)$

Rewrite the expression.

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{1}{2} \cdot - 1$

Combine $\frac{1}{2}$ and $- 1$ .

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} + \frac{- 1}{2}$

Move the negative in front of the fraction.

$\frac{d}{6} + \frac{2}{3} = \frac{d}{4} - \frac{1}{2}$

Step 3

Move all terms containing $d$ to the left side of the equation.

Subtract $\frac{d}{4}$ from both sides of the equation.

$\frac{d}{6} + \frac{2}{3} - \frac{d}{4} = - \frac{1}{2}$

To write $\frac{d}{6}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{d}{6} \cdot \frac{2}{2} - \frac{d}{4} + \frac{2}{3} = - \frac{1}{2}$

To write $- \frac{d}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{d}{6} \cdot \frac{2}{2} - \frac{d}{4} \cdot \frac{3}{3} + \frac{2}{3} = - \frac{1}{2}$

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{d}{6}$ by $\frac{2}{2}$ .

$\frac{d \cdot 2}{6 \cdot 2} - \frac{d}{4} \cdot \frac{3}{3} + \frac{2}{3} = - \frac{1}{2}$

Multiply $6$ by $2$ .

$\frac{d \cdot 2}{12} - \frac{d}{4} \cdot \frac{3}{3} + \frac{2}{3} = - \frac{1}{2}$

Multiply $\frac{d}{4}$ by $\frac{3}{3}$ .

$\frac{d \cdot 2}{12} - \frac{d \cdot 3}{4 \cdot 3} + \frac{2}{3} = - \frac{1}{2}$

Multiply $4$ by $3$ .

$\frac{d \cdot 2}{12} - \frac{d \cdot 3}{12} + \frac{2}{3} = - \frac{1}{2}$

Combine the numerators over the common denominator.

$\frac{d \cdot 2 - d \cdot 3}{12} + \frac{2}{3} = - \frac{1}{2}$

Simplify each term.

Simplify the numerator.

Factor $d$ out of $d \cdot 2 - d \cdot 3$ .

Factor $d$ out of $d \cdot 2$ .

$\frac{d (2) - d \cdot 3}{12} + \frac{2}{3} = - \frac{1}{2}$

Factor $d$ out of $- d \cdot 3$ .

$\frac{d (2) + d (- 1 \cdot 3)}{12} + \frac{2}{3} = - \frac{1}{2}$

Factor $d$ out of $d (2) + d (- 1 \cdot 3)$ .

$\frac{d (2 - 1 \cdot 3)}{12} + \frac{2}{3} = - \frac{1}{2}$

Multiply $- 1$ by $3$ .

$\frac{d (2 - 3)}{12} + \frac{2}{3} = - \frac{1}{2}$

Subtract $3$ from $2$ .

$\frac{d \cdot - 1}{12} + \frac{2}{3} = - \frac{1}{2}$

Move $- 1$ to the left of $d$ .

$\frac{- 1 \cdot d}{12} + \frac{2}{3} = - \frac{1}{2}$

Move the negative in front of the fraction.

$- \frac{d}{12} + \frac{2}{3} = - \frac{1}{2}$

Step 4

Move all terms not containing $d$ to the right side of the equation.

Subtract $\frac{2}{3}$ from both sides of the equation.

$- \frac{d}{12} = - \frac{1}{2} - \frac{2}{3}$

To write $- \frac{1}{2}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{d}{12} = - \frac{1}{2} \cdot \frac{3}{3} - \frac{2}{3}$

To write $- \frac{2}{3}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{d}{12} = - \frac{1}{2} \cdot \frac{3}{3} - \frac{2}{3} \cdot \frac{2}{2}$

Write each expression with a common denominator of $6$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{2}$ by $\frac{3}{3}$ .

$- \frac{d}{12} = - \frac{3}{2 \cdot 3} - \frac{2}{3} \cdot \frac{2}{2}$

Multiply $2$ by $3$ .

$- \frac{d}{12} = - \frac{3}{6} - \frac{2}{3} \cdot \frac{2}{2}$

Multiply $\frac{2}{3}$ by $\frac{2}{2}$ .

$- \frac{d}{12} = - \frac{3}{6} - \frac{2 \cdot 2}{3 \cdot 2}$

Multiply $3$ by $2$ .

$- \frac{d}{12} = - \frac{3}{6} - \frac{2 \cdot 2}{6}$

Combine the numerators over the common denominator.

$- \frac{d}{12} = \frac{- 3 - 2 \cdot 2}{6}$

Simplify the numerator.

Multiply $- 2$ by $2$ .

$- \frac{d}{12} = \frac{- 3 - 4}{6}$

Subtract $4$ from $- 3$ .

$- \frac{d}{12} = \frac{- 7}{6}$

Move the negative in front of the fraction.

$- \frac{d}{12} = - \frac{7}{6}$

Step 5

Multiply both sides of the equation by $- 12$ .

$- 12 (- \frac{d}{12}) = - 12 (- \frac{7}{6})$

Step 6

Simplify both sides of the equation.

Simplify the left side.

Simplify $- 12 (- \frac{d}{12})$ .

Cancel the common factor of $12$ .

Move the leading negative in $- \frac{d}{12}$ into the numerator.

$- 12 \frac{- d}{12} = - 12 (- \frac{7}{6})$

Factor $12$ out of $- 12$ .

$12 (- 1) \frac{- d}{12} = - 12 (- \frac{7}{6})$

Cancel the common factor.

$12 \cdot - 1 \frac{- d}{12} = - 12 (- \frac{7}{6})$

Rewrite the expression.

$- - d = - 12 (- \frac{7}{6})$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 d = - 12 (- \frac{7}{6})$

Multiply $d$ by $1$ .

$d = - 12 (- \frac{7}{6})$

Simplify the right side.

Simplify $- 12 (- \frac{7}{6})$ .

Cancel the common factor of $6$ .

Move the leading negative in $- \frac{7}{6}$ into the numerator.

$d = - 12 (\frac{- 7}{6})$

Factor $6$ out of $- 12$ .

$d = 6 (- 2) \frac{- 7}{6}$

Cancel the common factor.

$d = 6 \cdot - 2 \frac{- 7}{6}$

Rewrite the expression.

$d = - 2 \cdot - 7$

Multiply $- 2$ by $- 7$ .

$d = 14$

Solve for d 1/6d+2/3=1/4(d-2)

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