Solve for D -15y^4=(D)(3y^2)

$- 15 y^{4} = (D) (3 y^{2})$

Step 1

Rewrite the equation as $D \cdot (3 y^{2}) = - 15 y^{4}$ .

$D \cdot (3 y^{2}) = - 15 y^{4}$

Step 2

Divide each term in $(D \cdot (3 y^{2})) = - 15 y^{4}$ by $3 y^{2}$ and simplify.

Divide each term in $(D \cdot (3 y^{2})) = - 15 y^{4}$ by $3 y^{2}$ .

$\frac{(D \cdot (3 y^{2}))}{3 y^{2}} = \frac{- 15 y^{4}}{3 y^{2}}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{D \cdot 3 y^{2}}{3 y^{2}} = \frac{- 15 y^{4}}{3 y^{2}}$

Rewrite the expression.

$\frac{D y^{2}}{y^{2}} = \frac{- 15 y^{4}}{3 y^{2}}$

Cancel the common factor of $y^{2}$ .

Cancel the common factor.

$\frac{D y^{2}}{y^{2}} = \frac{- 15 y^{4}}{3 y^{2}}$

Divide $D$ by $1$ .

$D = \frac{- 15 y^{4}}{3 y^{2}}$

Simplify the right side.

Cancel the common factor of $- 15$ and $3$ .

Factor $3$ out of $- 15 y^{4}$ .

$D = \frac{3 (- 5 y^{4})}{3 y^{2}}$

Cancel the common factors.

Factor $3$ out of $3 y^{2}$ .

$D = \frac{3 (- 5 y^{4})}{3 (y^{2})}$

Cancel the common factor.

$D = \frac{3 (- 5 y^{4})}{3 y^{2}}$

Rewrite the expression.

$D = \frac{- 5 y^{4}}{y^{2}}$

Cancel the common factor of $y^{4}$ and $y^{2}$ .

Factor $y^{2}$ out of $- 5 y^{4}$ .

$D = \frac{y^{2} (- 5 y^{2})}{y^{2}}$

Cancel the common factors.

Multiply by $1$ .

$D = \frac{y^{2} (- 5 y^{2})}{y^{2} \cdot 1}$

Cancel the common factor.

$D = \frac{y^{2} (- 5 y^{2})}{y^{2} \cdot 1}$

Rewrite the expression.

$D = \frac{- 5 y^{2}}{1}$

Divide $- 5 y^{2}$ by $1$ .

$D = - 5 y^{2}$