Solve for d 19d-16d-d-d-1=12

$19 d - 16 d - d - d - 1 = 12$

Simplify $19 d - 16 d - d - d - 1$ .

Subtract $16 d$ from $19 d$ .

$3 d - d - d - 1 = 12$

Subtract $d$ from $3 d$ .

$2 d - d - 1 = 12$

Subtract $d$ from $2 d$ .

$d - 1 = 12$

Move all terms not containing $d$ to the right side of the equation.

Add $1$ to both sides of the equation.

$d = 12 + 1$

Add $12$ and $1$ .

$d = 13$