Solve for d 3+4d-14=15-5d-4d

$3 + 4 d - 14 = 15 - 5 d - 4 d$

Since $d$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$15 - 5 d - 4 d = 3 + 4 d - 14$

Subtract $4 d$ from $- 5 d$ .

$15 - 9 d = 3 + 4 d - 14$

Subtract $14$ from $3$ .

$15 - 9 d = 4 d - 11$

Move all terms containing $d$ to the left side of the equation.

Subtract $4 d$ from both sides of the equation.

$15 - 9 d - 4 d = - 11$

Subtract $4 d$ from $- 9 d$ .

$15 - 13 d = - 11$

Move all terms not containing $d$ to the right side of the equation.

Subtract $15$ from both sides of the equation.

$- 13 d = - 11 - 15$

Subtract $15$ from $- 11$ .

$- 13 d = - 26$

Divide each term in $- 13 d = - 26$ by $- 13$ and simplify.

Divide each term in $- 13 d = - 26$ by $- 13$ .

$\frac{- 13 d}{- 13} = \frac{- 26}{- 13}$

Simplify the left side.

Cancel the common factor of $- 13$ .

Cancel the common factor.

$\frac{- 13 d}{- 13} = \frac{- 26}{- 13}$

Divide $d$ by $1$ .

$d = \frac{- 26}{- 13}$

Simplify the right side.

Divide $- 26$ by $- 13$ .

$d = 2$