Solve for d 3(d+11)=6(d+33)

$3 (d + 11) = 6 (d + 33)$

Simplify $3 (d + 11)$ .

Start simplifying.

$0 + 0 + 3 (d + 11) = 6 (d + 33)$

Simplify by adding zeros.

$3 (d + 11) = 6 (d + 33)$

Apply the distributive property.

$3 d + 3 \cdot 11 = 6 (d + 33)$

Multiply $3$ by $11$ .

$3 d + 33 = 6 (d + 33)$

Simplify $6 (d + 33)$ .

Apply the distributive property.

$3 d + 33 = 6 d + 6 \cdot 33$

Multiply $6$ by $33$ .

$3 d + 33 = 6 d + 198$

Move all terms containing $d$ to the left side of the equation.

Subtract $6 d$ from both sides of the equation.

$3 d + 33 - 6 d = 198$

Subtract $6 d$ from $3 d$ .

$- 3 d + 33 = 198$

Move all terms not containing $d$ to the right side of the equation.

Subtract $33$ from both sides of the equation.

$- 3 d = 198 - 33$

Subtract $33$ from $198$ .

$- 3 d = 165$

Divide each term in $- 3 d = 165$ by $- 3$ and simplify.

Divide each term in $- 3 d = 165$ by $- 3$ .

$\frac{- 3 d}{- 3} = \frac{165}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 d}{- 3} = \frac{165}{- 3}$

Divide $d$ by $1$ .

$d = \frac{165}{- 3}$

Simplify the right side.

Divide $165$ by $- 3$ .

$d = - 55$