Solve for d 3(d-2)-2d>16

$3 (d - 2) - 2 d > 16$

Step 1

Simplify $3 (d - 2) - 2 d$ .

Simplify each term.

Apply the distributive property.

$3 d + 3 \cdot - 2 - 2 d > 16$

Multiply $3$ by $- 2$ .

$3 d - 6 - 2 d > 16$

Subtract $2 d$ from $3 d$ .

$d - 6 > 16$

Step 2

Move all terms not containing $d$ to the right side of the inequality.

Add $6$ to both sides of the inequality.

$d > 16 + 6$

Add $16$ and $6$ .

$d > 22$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$d > 22$

Interval Notation:

$(22, \infty)$