Solve for d 3d+10=d+2

$3 d + 10 = d + 2$

Step 1

Move all terms containing $d$ to the left side of the equation.

Subtract $d$ from both sides of the equation.

$3 d + 10 - d = 2$

Subtract $d$ from $3 d$ .

$2 d + 10 = 2$

Step 2

Move all terms not containing $d$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$2 d = 2 - 10$

Subtract $10$ from $2$ .

$2 d = - 8$

Step 3

Divide each term in $2 d = - 8$ by $2$ and simplify.

Divide each term in $2 d = - 8$ by $2$ .

$\frac{2 d}{2} = \frac{- 8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 d}{2} = \frac{- 8}{2}$

Divide $d$ by $1$ .

$d = \frac{- 8}{2}$

Simplify the right side.

Divide $- 8$ by $2$ .

$d = - 4$