Solve for d 4/5d+3=-2-1/5d

$\frac{4}{5} d + 3 = - 2 - \frac{1}{5} d$

Step 1

Combine $\frac{4}{5}$ and $d$ .

$\frac{4 d}{5} + 3 = - 2 - \frac{1}{5} d$

Step 2

Combine $d$ and $\frac{1}{5}$ .

$\frac{4 d}{5} + 3 = - 2 - \frac{d}{5}$

Step 3

Move all terms containing $d$ to the left side of the equation.

Add $\frac{d}{5}$ to both sides of the equation.

$\frac{4 d}{5} + 3 + \frac{d}{5} = - 2$

Combine the numerators over the common denominator.

$3 + \frac{4 d + d}{5} = - 2$

Add $4 d$ and $d$ .

$3 + \frac{5 d}{5} = - 2$

Cancel the common factor of $5$ .

Cancel the common factor.

$3 + \frac{5 d}{5} = - 2$

Divide $d$ by $1$ .

$3 + d = - 2$

Step 4

Move all terms not containing $d$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$d = - 2 - 3$

Subtract $3$ from $- 2$ .

$d = - 5$