Solve for d 7d+d-4d-7=5d

$7 d + d - 4 d - 7 = 5 d$

Simplify $7 d + d - 4 d - 7$ .

Add $7 d$ and $d$ .

$8 d - 4 d - 7 = 5 d$

Subtract $4 d$ from $8 d$ .

$4 d - 7 = 5 d$

Move all terms containing $d$ to the left side of the equation.

Subtract $5 d$ from both sides of the equation.

$4 d - 7 - 5 d = 0$

Subtract $5 d$ from $4 d$ .

$- d - 7 = 0$

Add $7$ to both sides of the equation.

$- d = 7$

Divide each term in $- d = 7$ by $- 1$ and simplify.

Divide each term in $- d = 7$ by $- 1$ .

$\frac{- d}{- 1} = \frac{7}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{d}{1} = \frac{7}{- 1}$

Divide $d$ by $1$ .

$d = \frac{7}{- 1}$

Simplify the right side.

Divide $7$ by $- 1$ .

$d = - 7$