Solve for d 9(d+3)+23=4D

$9 (d + 3) + 23 = 4 D$

Simplify $9 (d + 3) + 23$ .

Simplify each term.

Apply the distributive property.

$9 d + 9 \cdot 3 + 23 = 4 D$

Multiply $9$ by $3$ .

$9 d + 27 + 23 = 4 D$

Add $27$ and $23$ .

$9 d + 50 = 4 D$

Subtract $50$ from both sides of the equation.

$9 d = 4 D - 50$

Divide each term in $9 d = 4 D - 50$ by $9$ and simplify.

Divide each term in $9 d = 4 D - 50$ by $9$ .

$\frac{9 d}{9} = \frac{4 D}{9} + \frac{- 50}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 d}{9} = \frac{4 D}{9} + \frac{- 50}{9}$

Divide $d$ by $1$ .

$d = \frac{4 D}{9} + \frac{- 50}{9}$

Simplify the right side.

Move the negative in front of the fraction.

$d = \frac{4 D}{9} - \frac{50}{9}$