Solve for d 9d-7<=d+2

$9 d - 7 \leq d + 2$

Step 1

Move all terms containing $d$ to the left side of the inequality.

Subtract $d$ from both sides of the inequality.

$9 d - 7 - d \leq 2$

Subtract $d$ from $9 d$ .

$8 d - 7 \leq 2$

Step 2

Move all terms not containing $d$ to the right side of the inequality.

Add $7$ to both sides of the inequality.

$8 d \leq 2 + 7$

Add $2$ and $7$ .

$8 d \leq 9$

Step 3

Divide each term in $8 d \leq 9$ by $8$ and simplify.

Divide each term in $8 d \leq 9$ by $8$ .

$\frac{8 d}{8} \leq \frac{9}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 d}{8} \leq \frac{9}{8}$

Divide $d$ by $1$ .

$d \leq \frac{9}{8}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$d \leq \frac{9}{8}$

Interval Notation:

$(- \infty, \frac{9}{8}]$