Solve for d₂ a=1/2d_1d_2

$a = \frac{1}{2} d_{1} d_{2}$

Rewrite the equation as $\frac{1}{2} \cdot (d_{1} d_{2}) = a$ .

$\frac{1}{2} \cdot (d_{1} d_{2}) = a$

Multiply both sides of the equation by $2$ .

$2 (\frac{1}{2} \cdot (d_{1} d_{2})) = 2 a$

Simplify the left side.

Simplify $2 (\frac{1}{2} \cdot (d_{1} d_{2}))$ .

Multiply $\frac{1}{2} (d_{1} d_{2})$ .

Combine $d_{1}$ and $\frac{1}{2}$ .

$2 (\frac{d_{1}}{2} d_{2}) = 2 a$

Combine $\frac{d_{1}}{2}$ and $d_{2}$ .

$2 \frac{d_{1} d_{2}}{2} = 2 a$

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{d_{1} d_{2}}{2} = 2 a$

Rewrite the expression.

$d_{1} d_{2} = 2 a$

Divide each term in $d_{1} d_{2} = 2 a$ by $d_{1}$ and simplify.

Divide each term in $d_{1} d_{2} = 2 a$ by $d_{1}$ .

$\frac{d_{1} d_{2}}{d_{1}} = \frac{2 a}{d_{1}}$

Simplify the left side.

Cancel the common factor of $d_{1}$ .

Cancel the common factor.

$\frac{d_{1} d_{2}}{d_{1}} = \frac{2 a}{d_{1}}$

Divide $d_{2}$ by $1$ .

$d_{2} = \frac{2 a}{d_{1}}$