Solve for d |d+2|=6

$| d + 2 | = 6$

Step 1

Remove the absolute value term. This creates a $\pm$ on the right side of the equation because $| x | = \pm x$ .

$d + 2 = \pm 6$

Step 2

The complete solution is the result of both the positive and negative portions of the solution.

First, use the positive value of the $\pm$ to find the first solution.

$d + 2 = 6$

Move all terms not containing $d$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$d = 6 - 2$

Subtract $2$ from $6$ .

$d = 4$

Next, use the negative value of the $\pm$ to find the second solution.

$d + 2 = - 6$

Move all terms not containing $d$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$d = - 6 - 2$

Subtract $2$ from $- 6$ .

$d = - 8$

The complete solution is the result of both the positive and negative portions of the solution.

$d = 4, - 8$