Solve for d d+8=-d-10

$d + 8 = - d - 10$

Move all terms containing $d$ to the left side of the equation.

Add $d$ to both sides of the equation.

$d + 8 + d = - 10$

Add $d$ and $d$ .

$2 d + 8 = - 10$

Move all terms not containing $d$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$2 d = - 10 - 8$

Subtract $8$ from $- 10$ .

$2 d = - 18$

Divide each term in $2 d = - 18$ by $2$ and simplify.

Divide each term in $2 d = - 18$ by $2$ .

$\frac{2 d}{2} = \frac{- 18}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 d}{2} = \frac{- 18}{2}$

Divide $d$ by $1$ .

$d = \frac{- 18}{2}$

Simplify the right side.

Divide $- 18$ by $2$ .

$d = - 9$