Solve for d d=( cube root of 70)^3

$d = {(\sqrt[3]{70})}^{3}$

Remove parentheses.

$d = {\sqrt[3]{70}}^{3}$

Rewrite ${\sqrt[3]{70}}^{3}$ as $70$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{70}$ as $70^{\frac{1}{3}}$ .

$d = {(70^{\frac{1}{3}})}^{3}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$d = 70^{\frac{1}{3} \cdot 3}$

Combine $\frac{1}{3}$ and $3$ .

$d = 70^{\frac{3}{3}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$d = 70^{\frac{3}{3}}$

Rewrite the expression.

$d = 70^{1}$

Evaluate the exponent.

$d = 70$