Solve for d d=( square root of 23)^2

$d = {(\sqrt{23})}^{2}$

Step 1

Remove parentheses.

$d = {\sqrt{23}}^{2}$

Step 2

Rewrite ${\sqrt{23}}^{2}$ as $23$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{23}$ as $23^{\frac{1}{2}}$ .

$d = {(23^{\frac{1}{2}})}^{2}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$d = 23^{\frac{1}{2} \cdot 2}$

Combine $\frac{1}{2}$ and $2$ .

$d = 23^{\frac{2}{2}}$

Cancel the common factor of $2$ .

Cancel the common factor.

$d = 23^{\frac{2}{2}}$

Rewrite the expression.

$d = 23^{1}$

Evaluate the exponent.

$d = 23$