Solve for d f=110+0.12d

$f = 110 + 0.12 d$

Rewrite the equation as $110 + 0.12 d = f$ .

$110 + 0.12 d = f$

Subtract $110$ from both sides of the equation.

$0.12 d = f - 110$

Divide each term in $0.12 d = f - 110$ by $0.12$ and simplify.

Divide each term in $0.12 d = f - 110$ by $0.12$ .

$\frac{0.12 d}{0.12} = \frac{f}{0.12} + \frac{- 110}{0.12}$

Simplify the left side.

Cancel the common factor of $0.12$ .

Cancel the common factor.

$\frac{0.12 d}{0.12} = \frac{f}{0.12} + \frac{- 110}{0.12}$

Divide $d$ by $1$ .

$d = \frac{f}{0.12} + \frac{- 110}{0.12}$

Simplify the right side.

Simplify each term.

Multiply by $1$ .

$d = \frac{1 f}{0.12} + \frac{- 110}{0.12}$

Factor $0.12$ out of $0.12$ .

$d = \frac{1 f}{0.12 (1)} + \frac{- 110}{0.12}$

Separate fractions.

$d = \frac{1}{0.12} \cdot \frac{f}{1} + \frac{- 110}{0.12}$

Divide $1$ by $0.12$ .

$d = 8.\overline{3} \frac{f}{1} + \frac{- 110}{0.12}$

Divide $f$ by $1$ .

$d = 8.\overline{3} f + \frac{- 110}{0.12}$

Divide $- 110$ by $0.12$ .

$d = 8.\overline{3} f - 916.\overline{6}$