Solve for d square root of d=-6

$\sqrt{d} = - 6$

Step 1

To remove the radical on the left side of the equation, square both sides of the equation.

${\sqrt{d}}^{2} = {(- 6)}^{2}$

Step 2

Simplify each side of the equation.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{d}$ as $d^{\frac{1}{2}}$ .

${(d^{\frac{1}{2}})}^{2} = {(- 6)}^{2}$

Simplify the left side.

Simplify ${(d^{\frac{1}{2}})}^{2}$ .

Multiply the exponents in ${(d^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$d^{\frac{1}{2} \cdot 2} = {(- 6)}^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$d^{\frac{1}{2} \cdot 2} = {(- 6)}^{2}$

Rewrite the expression.

$d^{1} = {(- 6)}^{2}$

Simplify.

$d = {(- 6)}^{2}$

Simplify the right side.

Raise $- 6$ to the power of $2$ .

$d = 36$

Step 3

Exclude the solutions that do not make $\sqrt{d} = - 6$ true.

$No solution$