Solve for d V=pi/6d^3

$V = \frac{π}{6} d^{3}$

Step 1

Rewrite the equation as $\frac{π}{6} d^{3} = V$ .

$\frac{π}{6} d^{3} = V$

Step 2

Multiply both sides of the equation by $\frac{6}{π}$ .

$\frac{6}{π} (\frac{π}{6} d^{3}) = \frac{6}{π} V$

Step 3

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{6}{π} (\frac{π}{6} d^{3})$ .

Combine $\frac{π}{6}$ and $d^{3}$ .

$\frac{6}{π} \cdot \frac{π d^{3}}{6} = \frac{6}{π} V$

Combine.

$\frac{6 (π d^{3})}{π \cdot 6} = \frac{6}{π} V$

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 (π d^{3})}{π \cdot 6} = \frac{6}{π} V$

Rewrite the expression.

$\frac{π d^{3}}{π} = \frac{6}{π} V$

Cancel the common factor of $π$ .

Cancel the common factor.

$\frac{π d^{3}}{π} = \frac{6}{π} V$

Divide $d^{3}$ by $1$ .

$d^{3} = \frac{6}{π} V$

Simplify the right side.

Combine $\frac{6}{π}$ and $V$ .

$d^{3} = \frac{6 V}{π}$

Step 4

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$d = \sqrt[3]{\frac{6 V}{π}}$

Step 5

Simplify $\sqrt[3]{\frac{6 V}{π}}$ .

Rewrite $\sqrt[3]{\frac{6 V}{π}}$ as $\frac{\sqrt[3]{6 V}}{\sqrt[3]{π}}$ .

$d = \frac{\sqrt[3]{6 V}}{\sqrt[3]{π}}$

Multiply $\frac{\sqrt[3]{6 V}}{\sqrt[3]{π}}$ by $\frac{{\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{2}}$ .

$d = \frac{\sqrt[3]{6 V}}{\sqrt[3]{π}} \cdot \frac{{\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{2}}$

Combine and simplify the denominator.

Multiply $\frac{\sqrt[3]{6 V}}{\sqrt[3]{π}}$ by $\frac{{\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{2}}$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{\sqrt[3]{π} {\sqrt[3]{π}}^{2}}$

Raise $\sqrt[3]{π}$ to the power of $1$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{1} {\sqrt[3]{π}}^{2}}$

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{1 + 2}}$

Add $1$ and $2$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{{\sqrt[3]{π}}^{3}}$

Rewrite ${\sqrt[3]{π}}^{3}$ as $π$ .

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[3]{π}$ as $π^{\frac{1}{3}}$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{{(π^{\frac{1}{3}})}^{3}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{π^{\frac{1}{3} \cdot 3}}$

Combine $\frac{1}{3}$ and $3$ .

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{π^{\frac{3}{3}}}$

Cancel the common factor of $3$ .

Cancel the common factor.

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{π^{\frac{3}{3}}}$

Rewrite the expression.

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{π^{1}}$

Simplify.

$d = \frac{\sqrt[3]{6 V} {\sqrt[3]{π}}^{2}}{π}$

Rewrite ${\sqrt[3]{π}}^{2}$ as ${(π^{2})}^{\frac{1}{3}}$ .

$d = \frac{\sqrt[3]{6 V} \sqrt[3]{π^{2}}}{π}$

Combine using the product rule for radicals.

$d = \frac{\sqrt[3]{6 V π^{2}}}{π}$

Solve for d V=pi/6d^3

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