Solve for d2 (2(d_1-d_2))/L=W

$\frac{2 (d_{1} - d_{2})}{L} = W$

Step 1

Multiply both sides by $L$ .

$\frac{2 (d_{1} - d_{2})}{L} L = W L$

Step 2

Simplify the left side.

Simplify $\frac{2 (d_{1} - d_{2})}{L} L$ .

Cancel the common factor of $L$ .

Cancel the common factor.

$\frac{2 (d_{1} - d_{2})}{L} L = W L$

Rewrite the expression.

$2 (d_{1} - d_{2}) = W L$

Apply the distributive property.

$2 d_{1} + 2 (- d_{2}) = W L$

Multiply $- 1$ by $2$ .

$2 d_{1} - 2 d_{2} = W L$

Step 3

Solve for $d_{1}$ .

Add $2 d_{2}$ to both sides of the equation.

$2 d_{1} = W L + 2 d_{2}$

Divide each term in $2 d_{1} = W L + 2 d_{2}$ by $2$ and simplify.

Divide each term in $2 d_{1} = W L + 2 d_{2}$ by $2$ .

$\frac{2 d_{1}}{2} = \frac{W L}{2} + \frac{2 d_{2}}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 d_{1}}{2} = \frac{W L}{2} + \frac{2 d_{2}}{2}$

Divide $d_{1}$ by $1$ .

$d_{1} = \frac{W L}{2} + \frac{2 d_{2}}{2}$

Simplify the right side.

Cancel the common factor of $2$ .

Cancel the common factor.

$d_{1} = \frac{W L}{2} + \frac{2 d_{2}}{2}$

Divide $d_{2}$ by $1$ .

$d_{1} = \frac{W L}{2} + d_{2}$