Solve for d2 (3(d_1-d_2))/l=w

$\frac{3 (d_{1} - d_{2})}{l} = w$

Multiply both sides by $l$ .

$\frac{3 (d_{1} - d_{2})}{l} l = w l$

Simplify the left side.

Simplify $\frac{3 (d_{1} - d_{2})}{l} l$ .

Cancel the common factor of $l$ .

Cancel the common factor.

$\frac{3 (d_{1} - d_{2})}{l} l = w l$

Rewrite the expression.

$3 (d_{1} - d_{2}) = w l$

Apply the distributive property.

$3 d_{1} + 3 (- d_{2}) = w l$

Multiply $- 1$ by $3$ .

$3 d_{1} - 3 d_{2} = w l$

Solve for $d_{1}$ .

Add $3 d_{2}$ to both sides of the equation.

$3 d_{1} = w l + 3 d_{2}$

Divide each term in $3 d_{1} = w l + 3 d_{2}$ by $3$ and simplify.

Divide each term in $3 d_{1} = w l + 3 d_{2}$ by $3$ .

$\frac{3 d_{1}}{3} = \frac{w l}{3} + \frac{3 d_{2}}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 d_{1}}{3} = \frac{w l}{3} + \frac{3 d_{2}}{3}$

Divide $d_{1}$ by $1$ .

$d_{1} = \frac{w l}{3} + \frac{3 d_{2}}{3}$

Simplify the right side.

Cancel the common factor of $3$ .

Cancel the common factor.

$d_{1} = \frac{w l}{3} + \frac{3 d_{2}}{3}$

Divide $d_{2}$ by $1$ .

$d_{1} = \frac{w l}{3} + d_{2}$