Solve for f 2f+4>-7f+3

$2 f + 4 > - 7 f + 3$

Step 1

Move all terms containing $f$ to the left side of the inequality.

Add $7 f$ to both sides of the inequality.

$2 f + 4 + 7 f > 3$

Add $2 f$ and $7 f$ .

$9 f + 4 > 3$

Step 2

Move all terms not containing $f$ to the right side of the inequality.

Subtract $4$ from both sides of the inequality.

$9 f > 3 - 4$

Subtract $4$ from $3$ .

$9 f > - 1$

Step 3

Divide each term in $9 f > - 1$ by $9$ and simplify.

Divide each term in $9 f > - 1$ by $9$ .

$\frac{9 f}{9} > \frac{- 1}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 f}{9} > \frac{- 1}{9}$

Divide $f$ by $1$ .

$f > \frac{- 1}{9}$

Simplify the right side.

Move the negative in front of the fraction.

$f > - \frac{1}{9}$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$f > - \frac{1}{9}$

Interval Notation:

$(- \frac{1}{9}, \infty)$