Solve for f 75=3(-6f-5)

$75 = 3 (- 6 f - 5)$

Step 1

Rewrite the equation as $3 (- 6 f - 5) = 75$ .

$3 (- 6 f - 5) = 75$

Step 2

Divide each term in $3 (- 6 f - 5) = 75$ by $3$ and simplify.

Divide each term in $3 (- 6 f - 5) = 75$ by $3$ .

$\frac{3 (- 6 f - 5)}{3} = \frac{75}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (- 6 f - 5)}{3} = \frac{75}{3}$

Divide $- 6 f - 5$ by $1$ .

$- 6 f - 5 = \frac{75}{3}$

Simplify the right side.

Divide $75$ by $3$ .

$- 6 f - 5 = 25$

Step 3

Move all terms not containing $f$ to the right side of the equation.

Add $5$ to both sides of the equation.

$- 6 f = 25 + 5$

Add $25$ and $5$ .

$- 6 f = 30$

Step 4

Divide each term in $- 6 f = 30$ by $- 6$ and simplify.

Divide each term in $- 6 f = 30$ by $- 6$ .

$\frac{- 6 f}{- 6} = \frac{30}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 f}{- 6} = \frac{30}{- 6}$

Divide $f$ by $1$ .

$f = \frac{30}{- 6}$

Simplify the right side.

Divide $30$ by $- 6$ .

$f = - 5$