Solve for f f=-2+4/5f-3

$f = - 2 + \frac{4}{5} f - 3$

Simplify $- 2 + \frac{4}{5} f - 3$ .

Combine $\frac{4}{5}$ and $f$ .

$f = - 2 + \frac{4 f}{5} - 3$

Subtract $3$ from $- 2$ .

$f = \frac{4 f}{5} - 5$

Move all terms containing $f$ to the left side of the equation.

Subtract $\frac{4 f}{5}$ from both sides of the equation.

$f - \frac{4 f}{5} = - 5$

To write $f$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$f \cdot \frac{5}{5} - \frac{4 f}{5} = - 5$

Combine $f$ and $\frac{5}{5}$ .

$\frac{f \cdot 5}{5} - \frac{4 f}{5} = - 5$

Combine the numerators over the common denominator.

$\frac{f \cdot 5 - 4 f}{5} = - 5$

Simplify the numerator.

Move $5$ to the left of $f$ .

$\frac{5 \cdot f - 4 f}{5} = - 5$

Subtract $4 f$ from $5 f$ .

$\frac{f}{5} = - 5$

Multiply both sides of the equation by $5$ .

$5 \frac{f}{5} = 5 \cdot - 5$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$5 \frac{f}{5} = 5 \cdot - 5$

Rewrite the expression.

$f = 5 \cdot - 5$

Simplify the right side.

Multiply $5$ by $- 5$ .

$f = - 25$