Solve for f f=9/5(-15)+32

$f = \frac{9}{5} (- 15) + 32$

Multiply $\frac{9}{5}$ by $- 15$ .

$f = \frac{9}{5} \cdot - 15 + 32$

Simplify $\frac{9}{5} \cdot - 15 + 32$ .

Simplify each term.

Cancel the common factor of $5$ .

Factor $5$ out of $- 15$ .

$f = \frac{9}{5} \cdot (5 (- 3)) + 32$

Cancel the common factor.

$f = \frac{9}{5} \cdot (5 \cdot - 3) + 32$

Rewrite the expression.

$f = 9 \cdot - 3 + 32$

$f = 9 \cdot - 3 + 32$

Multiply $9$ by $- 3$ .

$f = - 27 + 32$

$f = - 27 + 32$

Add $- 27$ and $32$ .

$f = 5$

$f = 5$

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