Solve for F F(t)=2*1/(2^(3t))

$F (t) = 2 \cdot \frac{1}{2^{3 t}}$

Step 1

Combine $2$ and $\frac{1}{2^{3 t}}$ .

$F t = \frac{2}{2^{3 t}}$

Step 2

Divide each term in $F t = \frac{2}{2^{3 t}}$ by $t$ and simplify.

Divide each term in $F t = \frac{2}{2^{3 t}}$ by $t$ .

$\frac{F t}{t} = \frac{\frac{2}{2^{3 t}}}{t}$

Simplify the left side.

Cancel the common factor of $t$ .

Cancel the common factor.

$\frac{F t}{t} = \frac{\frac{2}{2^{3 t}}}{t}$

Divide $F$ by $1$ .

$F = \frac{\frac{2}{2^{3 t}}}{t}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$F = \frac{2}{2^{3 t}} \cdot \frac{1}{t}$

Combine.

$F = \frac{2 \cdot 1}{2^{3 t} t}$

Simplify the expression.

Multiply $2$ by $1$ .

$F = \frac{2}{2^{3 t} t}$

Reorder factors in $\frac{2}{2^{3 t} t}$ .

$F = \frac{2}{t \cdot 2^{3 t}}$