Solve for g 1/6g+3=4-1/3g

$\frac{1}{6} g + 3 = 4 - \frac{1}{3} g$

Combine $\frac{1}{6}$ and $g$ .

$\frac{g}{6} + 3 = 4 - \frac{1}{3} g$

Combine $g$ and $\frac{1}{3}$ .

$\frac{g}{6} + 3 = 4 - \frac{g}{3}$

Move all terms containing $g$ to the left side of the equation.

Add $\frac{g}{3}$ to both sides of the equation.

$\frac{g}{6} + 3 + \frac{g}{3} = 4$

To write $\frac{g}{3}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{g}{6} + \frac{g}{3} \cdot \frac{2}{2} + 3 = 4$

Write each expression with a common denominator of $6$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{g}{3}$ by $\frac{2}{2}$ .

$\frac{g}{6} + \frac{g \cdot 2}{3 \cdot 2} + 3 = 4$

Multiply $3$ by $2$ .

$\frac{g}{6} + \frac{g \cdot 2}{6} + 3 = 4$

Combine the numerators over the common denominator.

$\frac{g + g \cdot 2}{6} + 3 = 4$

Add $g$ and $g \cdot 2$ .

Reorder $g$ and $2$ .

$\frac{g + 2 \cdot g}{6} + 3 = 4$

Add $g$ and $2 \cdot g$ .

$\frac{3 g}{6} + 3 = 4$

Cancel the common factor of $3$ and $6$ .

Factor $3$ out of $3 g$ .

$\frac{3 (g)}{6} + 3 = 4$

Cancel the common factors.

Factor $3$ out of $6$ .

$\frac{3 g}{3 \cdot 2} + 3 = 4$

Cancel the common factor.

$\frac{3 g}{3 \cdot 2} + 3 = 4$

Rewrite the expression.

$\frac{g}{2} + 3 = 4$

Move all terms not containing $g$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$\frac{g}{2} = 4 - 3$

Subtract $3$ from $4$ .

$\frac{g}{2} = 1$

Multiply both sides of the equation by $2$ .

$2 \frac{g}{2} = 2 \cdot 1$

Simplify both sides of the equation.

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$2 \frac{g}{2} = 2 \cdot 1$

Rewrite the expression.

$g = 2 \cdot 1$

Simplify the right side.

Multiply $2$ by $1$ .

$g = 2$

Solve for g 1/6g+3=4-1/3g

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