Solve for g -10(g-6)=65

$- 10 (g - 6) = 65$

Divide each term in $- 10 (g - 6) = 65$ by $- 10$ and simplify.

Divide each term in $- 10 (g - 6) = 65$ by $- 10$ .

$\frac{- 10 (g - 6)}{- 10} = \frac{65}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 (g - 6)}{- 10} = \frac{65}{- 10}$

Divide $g - 6$ by $1$ .

$g - 6 = \frac{65}{- 10}$

Simplify the right side.

Cancel the common factor of $65$ and $- 10$ .

Factor $5$ out of $65$ .

$g - 6 = \frac{5 (13)}{- 10}$

Cancel the common factors.

Factor $5$ out of $- 10$ .

$g - 6 = \frac{5 \cdot 13}{5 \cdot - 2}$

Cancel the common factor.

$g - 6 = \frac{5 \cdot 13}{5 \cdot - 2}$

Rewrite the expression.

$g - 6 = \frac{13}{- 2}$

Move the negative in front of the fraction.

$g - 6 = - \frac{13}{2}$

Move all terms not containing $g$ to the right side of the equation.

Add $6$ to both sides of the equation.

$g = - \frac{13}{2} + 6$

To write $6$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$g = - \frac{13}{2} + 6 \cdot \frac{2}{2}$

Combine $6$ and $\frac{2}{2}$ .

$g = - \frac{13}{2} + \frac{6 \cdot 2}{2}$

Combine the numerators over the common denominator.

$g = \frac{- 13 + 6 \cdot 2}{2}$

Simplify the numerator.

Multiply $6$ by $2$ .

$g = \frac{- 13 + 12}{2}$

Add $- 13$ and $12$ .

$g = \frac{- 1}{2}$

Move the negative in front of the fraction.

$g = - \frac{1}{2}$

The result can be shown in multiple forms.

Exact Form:

$g = - \frac{1}{2}$

Decimal Form:

$g = - 0.5$