Solve for g -2/3+2g=-3/2g+3-2g

$- \frac{2}{3} + 2 g = - \frac{3}{2} g + 3 - 2 g$

Since $g$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$- \frac{3}{2} g + 3 - 2 g = - \frac{2}{3} + 2 g$

Simplify $- \frac{3}{2} g + 3 - 2 g$ .

Simplify each term.

Combine $g$ and $\frac{3}{2}$ .

$- \frac{g \cdot 3}{2} + 3 - 2 g = - \frac{2}{3} + 2 g$

Move $3$ to the left of $g$ .

$- \frac{3 g}{2} + 3 - 2 g = - \frac{2}{3} + 2 g$

To write $- 2 g$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{3 g}{2} - 2 g \cdot \frac{2}{2} + 3 = - \frac{2}{3} + 2 g$

Simplify terms.

Combine $- 2 g$ and $\frac{2}{2}$ .

$- \frac{3 g}{2} + \frac{- 2 g \cdot 2}{2} + 3 = - \frac{2}{3} + 2 g$

Combine the numerators over the common denominator.

$\frac{- 3 g - 2 g \cdot 2}{2} + 3 = - \frac{2}{3} + 2 g$

Simplify each term.

Simplify the numerator.

Factor $g$ out of $- 3 g - 2 g \cdot 2$ .

Factor $g$ out of $- 3 g$ .

$\frac{g \cdot - 3 - 2 g \cdot 2}{2} + 3 = - \frac{2}{3} + 2 g$

Factor $g$ out of $- 2 g \cdot 2$ .

$\frac{g \cdot - 3 + g (- 2 \cdot 2)}{2} + 3 = - \frac{2}{3} + 2 g$

Factor $g$ out of $g \cdot - 3 + g (- 2 \cdot 2)$ .

$\frac{g (- 3 - 2 \cdot 2)}{2} + 3 = - \frac{2}{3} + 2 g$

Multiply $- 2$ by $2$ .

$\frac{g (- 3 - 4)}{2} + 3 = - \frac{2}{3} + 2 g$

Subtract $4$ from $- 3$ .

$\frac{g \cdot - 7}{2} + 3 = - \frac{2}{3} + 2 g$

Move $- 7$ to the left of $g$ .

$\frac{- 7 \cdot g}{2} + 3 = - \frac{2}{3} + 2 g$

Move the negative in front of the fraction.

$- \frac{7 g}{2} + 3 = - \frac{2}{3} + 2 g$

Move all terms containing $g$ to the left side of the equation.

Subtract $2 g$ from both sides of the equation.

$- \frac{7 g}{2} + 3 - 2 g = - \frac{2}{3}$

To write $- 2 g$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- \frac{7 g}{2} - 2 g \cdot \frac{2}{2} + 3 = - \frac{2}{3}$

Combine $- 2 g$ and $\frac{2}{2}$ .

$- \frac{7 g}{2} + \frac{- 2 g \cdot 2}{2} + 3 = - \frac{2}{3}$

Combine the numerators over the common denominator.

$\frac{- 7 g - 2 g \cdot 2}{2} + 3 = - \frac{2}{3}$

Simplify each term.

Simplify the numerator.

Factor $g$ out of $- 7 g - 2 g \cdot 2$ .

Factor $g$ out of $- 7 g$ .

$\frac{g \cdot - 7 - 2 g \cdot 2}{2} + 3 = - \frac{2}{3}$

Factor $g$ out of $- 2 g \cdot 2$ .

$\frac{g \cdot - 7 + g (- 2 \cdot 2)}{2} + 3 = - \frac{2}{3}$

Factor $g$ out of $g \cdot - 7 + g (- 2 \cdot 2)$ .

$\frac{g (- 7 - 2 \cdot 2)}{2} + 3 = - \frac{2}{3}$

Multiply $- 2$ by $2$ .

$\frac{g (- 7 - 4)}{2} + 3 = - \frac{2}{3}$

Subtract $4$ from $- 7$ .

$\frac{g \cdot - 11}{2} + 3 = - \frac{2}{3}$

Move $- 11$ to the left of $g$ .

$\frac{- 11 \cdot g}{2} + 3 = - \frac{2}{3}$

Move the negative in front of the fraction.

$- \frac{11 g}{2} + 3 = - \frac{2}{3}$

Move all terms not containing $g$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- \frac{11 g}{2} = - \frac{2}{3} - 3$

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{11 g}{2} = - \frac{2}{3} - 3 \cdot \frac{3}{3}$

Combine $- 3$ and $\frac{3}{3}$ .

$- \frac{11 g}{2} = - \frac{2}{3} + \frac{- 3 \cdot 3}{3}$

Combine the numerators over the common denominator.

$- \frac{11 g}{2} = \frac{- 2 - 3 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 3$ by $3$ .

$- \frac{11 g}{2} = \frac{- 2 - 9}{3}$

Subtract $9$ from $- 2$ .

$- \frac{11 g}{2} = \frac{- 11}{3}$

Move the negative in front of the fraction.

$- \frac{11 g}{2} = - \frac{11}{3}$

Multiply both sides of the equation by $- \frac{2}{11}$ .

$- \frac{2}{11} (- \frac{11 g}{2}) = - \frac{2}{11} (- \frac{11}{3})$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{2}{11} (- \frac{11 g}{2})$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{2}{11}$ into the numerator.

$\frac{- 2}{11} (- \frac{11 g}{2}) = - \frac{2}{11} (- \frac{11}{3})$

Move the leading negative in $- \frac{11 g}{2}$ into the numerator.

$\frac{- 2}{11} \cdot \frac{- 11 g}{2} = - \frac{2}{11} (- \frac{11}{3})$

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{11} \cdot \frac{- 11 g}{2} = - \frac{2}{11} (- \frac{11}{3})$

Cancel the common factor.

$\frac{2 \cdot - 1}{11} \cdot \frac{- 11 g}{2} = - \frac{2}{11} (- \frac{11}{3})$

Rewrite the expression.

$\frac{- 1}{11} (- 11 g) = - \frac{2}{11} (- \frac{11}{3})$

Cancel the common factor of $11$ .

Factor $11$ out of $- 11 g$ .

$\frac{- 1}{11} (11 (- g)) = - \frac{2}{11} (- \frac{11}{3})$

Cancel the common factor.

$\frac{- 1}{11} (11 (- g)) = - \frac{2}{11} (- \frac{11}{3})$

Rewrite the expression.

$- - g = - \frac{2}{11} (- \frac{11}{3})$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 g = - \frac{2}{11} (- \frac{11}{3})$

Multiply $g$ by $1$ .

$g = - \frac{2}{11} (- \frac{11}{3})$

Simplify the right side.

Simplify $- \frac{2}{11} (- \frac{11}{3})$ .

Cancel the common factor of $11$ .

Move the leading negative in $- \frac{2}{11}$ into the numerator.

$g = \frac{- 2}{11} (- \frac{11}{3})$

Move the leading negative in $- \frac{11}{3}$ into the numerator.

$g = \frac{- 2}{11} \cdot \frac{- 11}{3}$

Factor $11$ out of $- 11$ .

$g = \frac{- 2}{11} \cdot \frac{11 (- 1)}{3}$

Cancel the common factor.

$g = \frac{- 2}{11} \cdot \frac{11 \cdot - 1}{3}$

Rewrite the expression.

$g = - 2 (\frac{- 1}{3})$

Combine $- 2$ and $\frac{- 1}{3}$ .

$g = \frac{- 2 \cdot - 1}{3}$

Multiply $- 2$ by $- 1$ .

$g = \frac{2}{3}$

The result can be shown in multiple forms.

Exact Form:

$g = \frac{2}{3}$

Decimal Form:

$g = 0.\overline{6}$

Solve for g -2/3+2g=-3/2g+3-2g

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