Solve for g -3(g-4)=2-3g

$- 3 (g - 4) = 2 - 3 g$

Step 1

Simplify $- 3 (g - 4)$ .

Rewrite.

$0 + 0 - 3 (g - 4) = 2 - 3 g$

Simplify by adding zeros.

$- 3 (g - 4) = 2 - 3 g$

Apply the distributive property.

$- 3 g - 3 \cdot - 4 = 2 - 3 g$

Multiply $- 3$ by $- 4$ .

$- 3 g + 12 = 2 - 3 g$

Step 2

Move all terms containing $g$ to the left side of the equation.

Add $3 g$ to both sides of the equation.

$- 3 g + 12 + 3 g = 2$

Combine the opposite terms in $- 3 g + 12 + 3 g$ .

Add $- 3 g$ and $3 g$ .

$0 + 12 = 2$

Add $0$ and $12$ .

$12 = 2$

Step 3

Since $12 \neq 2$ , there are no solutions.

No solution