Solve for g 3(g-7)=2(10+g)

$3 (g - 7) = 2 (10 + g)$

Simplify $3 (g - 7)$ .

Start simplifying.

$0 + 0 + 3 (g - 7) = 2 (10 + g)$

Simplify by adding zeros.

$3 (g - 7) = 2 (10 + g)$

Apply the distributive property.

$3 g + 3 \cdot - 7 = 2 (10 + g)$

Multiply $3$ by $- 7$ .

$3 g - 21 = 2 (10 + g)$

Simplify $2 (10 + g)$ .

Apply the distributive property.

$3 g - 21 = 2 \cdot 10 + 2 g$

Multiply $2$ by $10$ .

$3 g - 21 = 20 + 2 g$

Move all terms containing $g$ to the left side of the equation.

Subtract $2 g$ from both sides of the equation.

$3 g - 21 - 2 g = 20$

Subtract $2 g$ from $3 g$ .

$g - 21 = 20$

Move all terms not containing $g$ to the right side of the equation.

Add $21$ to both sides of the equation.

$g = 20 + 21$

Add $20$ and $21$ .

$g = 41$