Solve for g 4(g-1)=24

$4 (g - 1) = 24$

Step 1

Divide each term in $4 (g - 1) = 24$ by $4$ and simplify.

Divide each term in $4 (g - 1) = 24$ by $4$ .

$\frac{4 (g - 1)}{4} = \frac{24}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (g - 1)}{4} = \frac{24}{4}$

Divide $g - 1$ by $1$ .

$g - 1 = \frac{24}{4}$

Simplify the right side.

Divide $24$ by $4$ .

$g - 1 = 6$

Step 2

Move all terms not containing $g$ to the right side of the equation.

Add $1$ to both sides of the equation.

$g = 6 + 1$

Add $6$ and $1$ .

$g = 7$