Solve for g (4+g)(-11)=121

$(4 + g) (- 11) = 121$

Divide each term in $((4 + g) \cdot - 11) = 121$ by $- 11$ and simplify.

Divide each term in $((4 + g) \cdot - 11) = 121$ by $- 11$ .

$\frac{((4 + g) \cdot - 11)}{- 11} = \frac{121}{- 11}$

Simplify the left side.

Cancel the common factor of $- 11$ .

Cancel the common factor.

$\frac{(4 + g) \cdot - 11}{- 11} = \frac{121}{- 11}$

Divide $4 + g$ by $1$ .

$4 + g = \frac{121}{- 11}$

Simplify the right side.

Divide $121$ by $- 11$ .

$4 + g = - 11$

Move all terms not containing $g$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$g = - 11 - 4$

Subtract $4$ from $- 11$ .

$g = - 15$