Solve for g 5(g-2)+g=6(g-4)

$5 (g - 2) + g = 6 (g - 4)$

Simplify $5 (g - 2) + g$ .

Simplify each term.

Apply the distributive property.

$5 g + 5 \cdot - 2 + g = 6 (g - 4)$

Multiply $5$ by $- 2$ .

$5 g - 10 + g = 6 (g - 4)$

Add $5 g$ and $g$ .

$6 g - 10 = 6 (g - 4)$

Simplify $6 (g - 4)$ .

Apply the distributive property.

$6 g - 10 = 6 g + 6 \cdot - 4$

Multiply $6$ by $- 4$ .

$6 g - 10 = 6 g - 24$

Move all terms containing $g$ to the left side of the equation.

Subtract $6 g$ from both sides of the equation.

$6 g - 10 - 6 g = - 24$

Combine the opposite terms in $6 g - 10 - 6 g$ .

Subtract $6 g$ from $6 g$ .

$0 - 10 = - 24$

Subtract $10$ from $0$ .

$- 10 = - 24$

Since $- 10 \neq - 24$ , there are no solutions.

No solution