Solve for g 6(-2g-1)=-(13g+2)

$6 (- 2 g - 1) = - (13 g + 2)$

Step 1

Simplify $6 (- 2 g - 1)$ .

Start simplifying.

$0 + 0 + 6 (- 2 g - 1) = - (13 g + 2)$

Simplify by adding zeros.

$6 (- 2 g - 1) = - (13 g + 2)$

Apply the distributive property.

$6 (- 2 g) + 6 \cdot - 1 = - (13 g + 2)$

Multiply.

Multiply $- 2$ by $6$ .

$- 12 g + 6 \cdot - 1 = - (13 g + 2)$

Multiply $6$ by $- 1$ .

$- 12 g - 6 = - (13 g + 2)$

Step 2

Simplify $- (13 g + 2)$ .

Apply the distributive property.

$- 12 g - 6 = - (13 g) - 1 \cdot 2$

Multiply.

Multiply $13$ by $- 1$ .

$- 12 g - 6 = - 13 g - 1 \cdot 2$

Multiply $- 1$ by $2$ .

$- 12 g - 6 = - 13 g - 2$

Step 3

Move all terms containing $g$ to the left side of the equation.

Add $13 g$ to both sides of the equation.

$- 12 g - 6 + 13 g = - 2$

Add $- 12 g$ and $13 g$ .

$g - 6 = - 2$

Step 4

Move all terms not containing $g$ to the right side of the equation.

Add $6$ to both sides of the equation.

$g = - 2 + 6$

Add $- 2$ and $6$ .

$g = 4$