Solve for g -6g+3g+12>-18

$- 6 g + 3 g + 12 > - 18$

Step 1

Add $- 6 g$ and $3 g$ .

$- 3 g + 12 > - 18$

Step 2

Move all terms not containing $g$ to the right side of the inequality.

Subtract $12$ from both sides of the inequality.

$- 3 g > - 18 - 12$

Subtract $12$ from $- 18$ .

$- 3 g > - 30$

Step 3

Divide each term in $- 3 g > - 30$ by $- 3$ and simplify.

Divide each term in $- 3 g > - 30$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 g}{- 3} < \frac{- 30}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 g}{- 3} < \frac{- 30}{- 3}$

Divide $g$ by $1$ .

$g < \frac{- 30}{- 3}$

Simplify the right side.

Divide $- 30$ by $- 3$ .

$g < 10$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$g < 10$

Interval Notation:

$(- \infty, 10)$

Solve for g -6g+3g+12>-18

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