Solve for g -98+2(18g+11)=40g

$- 98 + 2 (18 g + 11) = 40 g$

Simplify $- 98 + 2 (18 g + 11)$ .

Simplify each term.

Apply the distributive property.

$- 98 + 2 (18 g) + 2 \cdot 11 = 40 g$

Multiply $18$ by $2$ .

$- 98 + 36 g + 2 \cdot 11 = 40 g$

Multiply $2$ by $11$ .

$- 98 + 36 g + 22 = 40 g$

Add $- 98$ and $22$ .

$36 g - 76 = 40 g$

Move all terms containing $g$ to the left side of the equation.

Subtract $40 g$ from both sides of the equation.

$36 g - 76 - 40 g = 0$

Subtract $40 g$ from $36 g$ .

$- 4 g - 76 = 0$

Add $76$ to both sides of the equation.

$- 4 g = 76$

Divide each term in $- 4 g = 76$ by $- 4$ and simplify.

Divide each term in $- 4 g = 76$ by $- 4$ .

$\frac{- 4 g}{- 4} = \frac{76}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 g}{- 4} = \frac{76}{- 4}$

Divide $g$ by $1$ .

$g = \frac{76}{- 4}$

Simplify the right side.

Divide $76$ by $- 4$ .

$g = - 19$