Solve for g 9g=3(-4+5g)

$9 g = 3 (- 4 + 5 g)$

Simplify $3 (- 4 + 5 g)$ .

Apply the distributive property.

$9 g = 3 \cdot - 4 + 3 (5 g)$

Multiply.

Multiply $3$ by $- 4$ .

$9 g = - 12 + 3 (5 g)$

Multiply $5$ by $3$ .

$9 g = - 12 + 15 g$

Move all terms containing $g$ to the left side of the equation.

Subtract $15 g$ from both sides of the equation.

$9 g - 15 g = - 12$

Subtract $15 g$ from $9 g$ .

$- 6 g = - 12$

Divide each term in $- 6 g = - 12$ by $- 6$ and simplify.

Divide each term in $- 6 g = - 12$ by $- 6$ .

$\frac{- 6 g}{- 6} = \frac{- 12}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 g}{- 6} = \frac{- 12}{- 6}$

Divide $g$ by $1$ .

$g = \frac{- 12}{- 6}$

Simplify the right side.

Divide $- 12$ by $- 6$ .

$g = 2$