Solve for g 9g+9-12g=19g+9

$9 g + 9 - 12 g = 19 g + 9$

Subtract $12 g$ from $9 g$ .

$- 3 g + 9 = 19 g + 9$

Move all terms containing $g$ to the left side of the equation.

Subtract $19 g$ from both sides of the equation.

$- 3 g + 9 - 19 g = 9$

Subtract $19 g$ from $- 3 g$ .

$- 22 g + 9 = 9$

Move all terms not containing $g$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$- 22 g = 9 - 9$

Subtract $9$ from $9$ .

$- 22 g = 0$

Divide each term in $- 22 g = 0$ by $- 22$ and simplify.

Divide each term in $- 22 g = 0$ by $- 22$ .

$\frac{- 22 g}{- 22} = \frac{0}{- 22}$

Simplify the left side.

Cancel the common factor of $- 22$ .

Cancel the common factor.

$\frac{- 22 g}{- 22} = \frac{0}{- 22}$

Divide $g$ by $1$ .

$g = \frac{0}{- 22}$

Simplify the right side.

Divide $0$ by $- 22$ .

$g = 0$