Solve for G D=2/3(F-G)

$D = \frac{2}{3} (F - G)$

Rewrite the equation as $\frac{2}{3} \cdot (F - G) = D$ .

$\frac{2}{3} \cdot (F - G) = D$

Multiply both sides of the equation by $\frac{3}{2}$ .

$\frac{3}{2} (\frac{2}{3} \cdot (F - G)) = \frac{3}{2} D$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{3}{2} (\frac{2}{3} \cdot (F - G))$ .

Apply the distributive property.

$\frac{3}{2} (\frac{2}{3} F + \frac{2}{3} (- G)) = \frac{3}{2} D$

Combine $\frac{2}{3}$ and $F$ .

$\frac{3}{2} (\frac{2 F}{3} + \frac{2}{3} (- G)) = \frac{3}{2} D$

Combine $\frac{2}{3}$ and $G$ .

$\frac{3}{2} (\frac{2 F}{3} - \frac{2 G}{3}) = \frac{3}{2} D$

Apply the distributive property.

$\frac{3}{2} \cdot \frac{2 F}{3} + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3}{2} \cdot \frac{2 F}{3} + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Rewrite the expression.

$\frac{1}{2} (2 F) + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Cancel the common factor of $2$ .

Factor $2$ out of $2 F$ .

$\frac{1}{2} (2 (F)) + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Cancel the common factor.

$\frac{1}{2} (2 F) + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Rewrite the expression.

$F + \frac{3}{2} (- \frac{2 G}{3}) = \frac{3}{2} D$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{2 G}{3}$ into the numerator.

$F + \frac{3}{2} \cdot \frac{- 2 G}{3} = \frac{3}{2} D$

Cancel the common factor.

$F + \frac{3}{2} \cdot \frac{- 2 G}{3} = \frac{3}{2} D$

Rewrite the expression.

$F + \frac{1}{2} (- 2 G) = \frac{3}{2} D$

Cancel the common factor of $2$ .

Factor $2$ out of $- 2 G$ .

$F + \frac{1}{2} (2 (- G)) = \frac{3}{2} D$

Cancel the common factor.

$F + \frac{1}{2} (2 (- G)) = \frac{3}{2} D$

Rewrite the expression.

$F - G = \frac{3}{2} D$

Simplify the right side.

Combine $\frac{3}{2}$ and $D$ .

$F - G = \frac{3 D}{2}$

Subtract $F$ from both sides of the equation.

$- G = \frac{3 D}{2} - F$

Divide each term in $- G = \frac{3 D}{2} - F$ by $- 1$ and simplify.

Divide each term in $- G = \frac{3 D}{2} - F$ by $- 1$ .

$\frac{- G}{- 1} = \frac{\frac{3 D}{2}}{- 1} + \frac{- F}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{G}{1} = \frac{\frac{3 D}{2}}{- 1} + \frac{- F}{- 1}$

Divide $G$ by $1$ .

$G = \frac{\frac{3 D}{2}}{- 1} + \frac{- F}{- 1}$

Simplify the right side.

Simplify each term.

Move the negative one from the denominator of $\frac{\frac{3 D}{2}}{- 1}$ .

$G = - 1 \cdot \frac{3 D}{2} + \frac{- F}{- 1}$

Rewrite $- 1 \cdot \frac{3 D}{2}$ as $- \frac{3 D}{2}$ .

$G = - \frac{3 D}{2} + \frac{- F}{- 1}$

Dividing two negative values results in a positive value.

$G = - \frac{3 D}{2} + \frac{F}{1}$

Divide $F$ by $1$ .

$G = - \frac{3 D}{2} + F$

Solve for G D=2/3(F-G)

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