Solve for G d=5/6(F+G)

$d = \frac{5}{6} (F + G)$

Rewrite the equation as $\frac{5}{6} \cdot (F + G) = d$ .

$\frac{5}{6} \cdot (F + G) = d$

Multiply both sides of the equation by $\frac{6}{5}$ .

$\frac{6}{5} (\frac{5}{6} \cdot (F + G)) = \frac{6}{5} d$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{6}{5} (\frac{5}{6} \cdot (F + G))$ .

Apply the distributive property.

$\frac{6}{5} (\frac{5}{6} F + \frac{5}{6} G) = \frac{6}{5} d$

Combine $\frac{5}{6}$ and $F$ .

$\frac{6}{5} (\frac{5 F}{6} + \frac{5}{6} G) = \frac{6}{5} d$

Combine $\frac{5}{6}$ and $G$ .

$\frac{6}{5} (\frac{5 F}{6} + \frac{5 G}{6}) = \frac{6}{5} d$

Apply the distributive property.

$\frac{6}{5} \cdot \frac{5 F}{6} + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6}{5} \cdot \frac{5 F}{6} + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Rewrite the expression.

$\frac{1}{5} (5 F) + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Cancel the common factor of $5$ .

Factor $5$ out of $5 F$ .

$\frac{1}{5} (5 (F)) + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Cancel the common factor.

$\frac{1}{5} (5 F) + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Rewrite the expression.

$F + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Cancel the common factor of $6$ .

Cancel the common factor.

$F + \frac{6}{5} \cdot \frac{5 G}{6} = \frac{6}{5} d$

Rewrite the expression.

$F + \frac{1}{5} (5 G) = \frac{6}{5} d$

Cancel the common factor of $5$ .

Factor $5$ out of $5 G$ .

$F + \frac{1}{5} (5 (G)) = \frac{6}{5} d$

Cancel the common factor.

$F + \frac{1}{5} (5 G) = \frac{6}{5} d$

Rewrite the expression.

$F + G = \frac{6}{5} d$

Simplify the right side.

Combine $\frac{6}{5}$ and $d$ .

$F + G = \frac{6 d}{5}$

Subtract $F$ from both sides of the equation.

$G = \frac{6 d}{5} - F$