Solve for g -g+2(3+g)=-4(g+1)

$- g + 2 (3 + g) = - 4 (g + 1)$

Simplify $- g + 2 (3 + g)$ .

Simplify each term.

Apply the distributive property.

$- g + 2 \cdot 3 + 2 g = - 4 (g + 1)$

Multiply $2$ by $3$ .

$- g + 6 + 2 g = - 4 (g + 1)$

Add $- g$ and $2 g$ .

$g + 6 = - 4 (g + 1)$

Simplify $- 4 (g + 1)$ .

Apply the distributive property.

$g + 6 = - 4 g - 4 \cdot 1$

Multiply $- 4$ by $1$ .

$g + 6 = - 4 g - 4$

Move all terms containing $g$ to the left side of the equation.

Add $4 g$ to both sides of the equation.

$g + 6 + 4 g = - 4$

Add $g$ and $4 g$ .

$5 g + 6 = - 4$

Move all terms not containing $g$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$5 g = - 4 - 6$

Subtract $6$ from $- 4$ .

$5 g = - 10$

Divide each term in $5 g = - 10$ by $5$ and simplify.

Divide each term in $5 g = - 10$ by $5$ .

$\frac{5 g}{5} = \frac{- 10}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 g}{5} = \frac{- 10}{5}$

Divide $g$ by $1$ .

$g = \frac{- 10}{5}$

Simplify the right side.

Divide $- 10$ by $5$ .

$g = - 2$