Solve for g (g+4)-3g=1+g

$(g + 4) - 3 g = 1 + g$

Step 1

Subtract $3 g$ from $g$ .

$- 2 g + 4 = 1 + g$

Step 2

Move all terms containing $g$ to the left side of the equation.

Subtract $g$ from both sides of the equation.

$- 2 g + 4 - g = 1$

Subtract $g$ from $- 2 g$ .

$- 3 g + 4 = 1$

Step 3

Move all terms not containing $g$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 3 g = 1 - 4$

Subtract $4$ from $1$ .

$- 3 g = - 3$

Step 4

Divide each term in $- 3 g = - 3$ by $- 3$ and simplify.

Divide each term in $- 3 g = - 3$ by $- 3$ .

$\frac{- 3 g}{- 3} = \frac{- 3}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 g}{- 3} = \frac{- 3}{- 3}$

Divide $g$ by $1$ .

$g = \frac{- 3}{- 3}$

Simplify the right side.

Divide $- 3$ by $- 3$ .

$g = 1$