Solve for h 1/2(6h-4)=-5h+1

$\frac{1}{2} (6 h - 4) = - 5 h + 1$

Step 1

Simplify $\frac{1}{2} \cdot (6 h - 4)$ .

Rewrite.

$0 + 0 + \frac{1}{2} \cdot (6 h - 4) = - 5 h + 1$

Simplify by adding zeros.

$\frac{1}{2} \cdot (6 h - 4) = - 5 h + 1$

Apply the distributive property.

$\frac{1}{2} (6 h) + \frac{1}{2} \cdot - 4 = - 5 h + 1$

Cancel the common factor of $2$ .

Factor $2$ out of $6 h$ .

$\frac{1}{2} (2 (3 h)) + \frac{1}{2} \cdot - 4 = - 5 h + 1$

Cancel the common factor.

$\frac{1}{2} (2 (3 h)) + \frac{1}{2} \cdot - 4 = - 5 h + 1$

Rewrite the expression.

$3 h + \frac{1}{2} \cdot - 4 = - 5 h + 1$

Cancel the common factor of $2$ .

Factor $2$ out of $- 4$ .

$3 h + \frac{1}{2} \cdot (2 (- 2)) = - 5 h + 1$

Cancel the common factor.

$3 h + \frac{1}{2} \cdot (2 \cdot - 2) = - 5 h + 1$

Rewrite the expression.

$3 h - 2 = - 5 h + 1$

Step 2

Move all terms containing $h$ to the left side of the equation.

Add $5 h$ to both sides of the equation.

$3 h - 2 + 5 h = 1$

Add $3 h$ and $5 h$ .

$8 h - 2 = 1$

Step 3

Move all terms not containing $h$ to the right side of the equation.

Add $2$ to both sides of the equation.

$8 h = 1 + 2$

Add $1$ and $2$ .

$8 h = 3$

Step 4

Divide each term in $8 h = 3$ by $8$ and simplify.

Divide each term in $8 h = 3$ by $8$ .

$\frac{8 h}{8} = \frac{3}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 h}{8} = \frac{3}{8}$

Divide $h$ by $1$ .

$h = \frac{3}{8}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$h = \frac{3}{8}$

Decimal Form:

$h = 0.375$

Solve for h 1/2(6h-4)=-5h+1

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