Solve for H 1.5=- log of H

$1.5 = - \log (H)$

Rewrite the equation as $- \log (H) = 1.5$ .

$- \log (H) = 1.5$

Divide each term in $- \log (H) = 1.5$ by $- 1$ and simplify.

Divide each term in $- \log (H) = 1.5$ by $- 1$ .

$\frac{- \log (H)}{- 1} = \frac{1.5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{\log (H)}{1} = \frac{1.5}{- 1}$

Divide $\log (H)$ by $1$ .

$\log (H) = \frac{1.5}{- 1}$

Simplify the right side.

Divide $1.5$ by $- 1$ .

$\log (H) = - 1.5$

Rewrite $\log (H) = - 1.5$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$10^{- 1.5} = H$

Solve for $H$ .

Rewrite the equation as $H = 10^{- 1.5}$ .

$H = 10^{- 1.5}$

Simplify $10^{- 1.5}$ .

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$H = \frac{1}{10^{1.5}}$

Raise $10$ to the power of $1.5$ .

$H = \frac{1}{31.6227766}$

Divide $1$ by $31.6227766$ .

$H = 0.03162277$

Solve for H 1.5=- log of H

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