Solve for h 2(h+1)=5h-7

$2 (h + 1) = 5 h - 7$

Simplify $2 (h + 1)$ .

Rewrite.

$0 + 0 + 2 (h + 1) = 5 h - 7$

Simplify by adding zeros.

$2 (h + 1) = 5 h - 7$

Apply the distributive property.

$2 h + 2 \cdot 1 = 5 h - 7$

Multiply $2$ by $1$ .

$2 h + 2 = 5 h - 7$

Move all terms containing $h$ to the left side of the equation.

Subtract $5 h$ from both sides of the equation.

$2 h + 2 - 5 h = - 7$

Subtract $5 h$ from $2 h$ .

$- 3 h + 2 = - 7$

Move all terms not containing $h$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$- 3 h = - 7 - 2$

Subtract $2$ from $- 7$ .

$- 3 h = - 9$

Divide each term in $- 3 h = - 9$ by $- 3$ and simplify.

Divide each term in $- 3 h = - 9$ by $- 3$ .

$\frac{- 3 h}{- 3} = \frac{- 9}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 h}{- 3} = \frac{- 9}{- 3}$

Divide $h$ by $1$ .

$h = \frac{- 9}{- 3}$

Simplify the right side.

Divide $- 9$ by $- 3$ .

$h = 3$